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Electron Beam Experiment to get the set of V and I values that will produce a beam of radius 5 cm. watch this short video show all work https://www.youtube.com/watch?v=CyEMzKbWqjo VERY short lab.There...

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Electron Beam Experiment to get the set of V and I values that will produce a beam of radius 5 cm. watch this short video show all work
https://www.youtube.com/watch?v=CyEMzKbWqjo

VERY short lab.There is a link to do lab all info is there for lab. please show work clearly and do conclusion.
The conclusion should include what was done in the lab. how the lab was accomplish. what is the lab results indicate. what you learned , what you already knew and how the lab can be applied to real life. please at least put one example for used in everyday life.


Answered 3 days After Oct 20, 2021

Solution

Neelakshi answered on Oct 23 2021
134 Votes
Lab 6: Kirchhoff’s Rules
Name _____________________________ Date___________
Lab Partner(s) _____________________________________
Laboratory Report
NOTE: Show all your calculations. If needed, include additional pages, or do your work on a
separate sheet and insert a scanned copy or picture to your lab report. Your grade will
drastically be reduced if no work is shown.
Theory
The electron's equation of motion is given by the Lorentz relation. If there is no electric field, this can be
written as
FB=−e(v×B)
where FBFB is the magnetic force on the electron, −e = -1.6×10-19 coulombs are the electric charge of
the electron, v is the velocity of the electron, and B is the magnetic field. If electron moves in an
o
it perpendicular to the magnetic field, the helical path becomes a circular path, and the magnitude of
the magnetic force is
FB=evB
Recall from Physics 6A that an object traveling around a circle experiences a centripetal force. For an
electron of mass m moving at speed v in a circle of radius R, the magnitude of the centripetal force FC is
FC=mv2/R
evB=mv2/R
eB=mv/R
The initial potential energy of the electrons in this experiment is eV, where V is the accelerating voltage
used in the electron-beam tube. After the electrons are accelerated through a voltage V, this initial
potential energy is converted into kinetic energy (1/2)mv2. Since energy is conserved, it follows that
eV=(1/2)mv2
Combining Eqs. 4 and 5 yields
e/m=2V/B2R2
Objective
Quantities like charge and mass are extremely small (ee = 1.60217733×10-19 coulombs, mm =
9.1093897×10-31 kilograms). The ratio of these two fundamental constants can be obtained from the
adius of curvature of an electron beam traveling in a known magnetic field. An electron beam of a
specified energy, and...
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