Great Deal! Get Instant $10 FREE in Account on First Order + 10% Cashback on Every Order Order Now

Determine the value of c for the distribution of random variable X that has a discrete distribution with the following probability function, f(x) =  cx for x = 1, . . . , 5 0 otherwise [2 marks] Data...

1 answer below »
Determine the value of c for the distribution of random variable X that has a discrete distribution with the following probability function, f(x) =  cx for x = 1, . . . , 5 0 otherwise [2 marks] Data Source: Probability and Statistics M. DeGroot & M. Schervish, Addison-Wesley XXXXXXXXXXb) Let X be the ticket price for an event. supose that the probability distribution of X is: X XXXXXXXXXX 200 p XXXXXXXXXX XXXXXXXXXXi) What is the probability that a randomly selected attendee paid more that $140 for the ticket? [2 marks] (ii) What is the probability that a randomly selected attendee paid less than $160? [2 marks] (iii) Compute the expected value and standard deviation of X. [4 marks] Data Source: Statistics and data with R. Y. Cohen & J. Cohen, Wiley XXXXXXXXXXQuestion 2 - 6 marks Suppose that a box contains 7 red balls and and 3 blue balls. If 5 balls are selected at random, without replacement, determine the probability function of the number of red balls that will be obtained using (a) Counting methods 3 marks (b) Simulation 3 marks . Data Source: Probability and Statistics M. DeGroot & M. Schervish, Addison-Wesley XXXXXXXXXXQuestion 3 - 8 marks Suppose that the life expectancy X of each member of a group of people is a random variable having an exponential distribution with parameter ? = 1 50 years. (a) For an individual from this group, compute the probability that: (i) He will survive to 65, 2 marks (ii) He will live to be at least 70 years old, given that he just celebrated his 40th birthday, 3 marks (b) For what value of c is P(X > c) = 1 2 ? 3 marks f(x|?) = ?e-?x ? > 0, x > 0 Data Source: A Course in Mathematical Statistics. G Roussas, Academic Press XXXXXXXXXXQuestion 4 - 6 marks A uniform distribution is defined with density function f(x; a, ß) = 1 (ß - a) ß > a and x ? (a, ß) Show that (a) E(X) = a + ß 2 [2 marks] (b) var(X) = (ß - a) 2 12 [4 marks] Data Source: A Course in Mathematical Statistics. G Roussas, Academic Press XXXXXXXXXXQuestion 5 - 6 marks Let X be a random variable with probability density function f(x) = ?e-?(x-a) x > a (a) Find its Moment Generating Function MX(t) for those t’s that exist. [3 marks] (b) Calculate E(X) [1 mark] (c) Calculate s 2 (X) [2 marks] Data Source: A Course in Mathematical Statistics. G Roussas, Academic Press (1997)
Answered Same Day Dec 23, 2021

Solution

David answered on Dec 23 2021
137 Votes
Q1 (a)
    Determine the value of c for the distribution of random variable X that has a discrete
distribution with the following probability function,
f(x) =
1,2,3,4,5
0
cxforx
Otherwise
=
ì
í
î
Solution: The probability distribution table:
X
1
2
3
4
5
P(X)
c
2c
3c
4c
5c
We know that ∑P(x) = 1
c+2c+3c+4c+5c = 1
15c = 1
Answer: c = 1/15
    
    (i) What is the probability that a randomly selected attendee paid more that $140 for the ticket?
P(x>140) = P(x = 160)+ P(x = 180) + P(x = 200)
=0.16 + 0.13 + 0.11
= 0.40
Answer: P(x>140) = 0.40
    
    (ii) What is the probability that a randomly selected attendee paid less than $160?
P(x<160) = P(x = 100)+ P(x = 120) + P(x = 140)
=0.22 + 0.20 + 0.18
= 0.60
Answer: P(x<160) = 0.60
    
    (iii) Compute the expected value and standard deviation of X.
X
100
120
140
160
180
200
∑
P(X)
0.22
0.20
0.18
0.16
0.13
0.11
XP(X)
22
24
25.2
25.6
23.4
22
142.2
X2P(X)
2200
2880
3528
4096
4212
4400
21316
Expected value = E(X) = ∑x.P(x)
= 100(0.22) + 120(0.20) + 140(0.18) + 160(0.16) +180(0.13) + 200(0.11)
= 22 + 24 + 25.2 + 25.6 + 23.4 + 22
= 142.2
Standard deviation =
s
(X) =
(
)
2
2
()()
xPxEX
-
Ã¥
=
(
)
2
21316142.2
-
=
2131620220.84
-
=
1095.16
= 33.09
Answer: The expected value of X = 142.2 and standard deviation of X = 33.09
    2(a)
    Number of red balls = 7
Number of blue balls = 3
5 balls are drawn randomly without replacement
So the all possibilities are as follows
Either (2 red and 3 blue balls) or (3 red and 2 blue balls) or (24 red and 1 blue balls) or(5 red and 0 blue ball)
The probabilities will be as follows
P(2 red and 3 blue) =
73
23
10
5
CC
C
´
=
21
252
=
1
12
P(3 red and 2 blue) =
73
32
10
5
CC
C
´
=
5
12
P(4 red and 1 blue)...
SOLUTION.PDF

Answer To This Question Is Available To Download

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here