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could you complete these 3 questions?

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Answered Same Day May 20, 2021

Solution

Rajeswari answered on May 20 2021
157 Votes
Area under the curve
The intersection (1/sqrt 2, pi/4) divides into two regions
Area = region under sin ^(-1) x +region under cos ^(-1)x
=+
I integral
=
II integral
=
Adding we get area =
Qno.5:
By applying integration by parts for v’ = e^x
=
We applied fundamental theorem of...
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