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Chapter 10 Problems 1. A helium filled party balloon has a volume of 4.50 L at sea level, where the atmospheric pressure is 748 Torr. Assuming that the temperature remains constant, what will be the...

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Chapter 10 Problems
1. A helium filled party balloon has a volume of 4.50 L at sea level, where the atmospheric
pressure is 748 To
. Assuming that the temperature remains constant, what will be the
volume of the balloon when it is taken to a mountain resort at an altitude of 2500 m where
the atmospheric pressure is 557 To
? (What gas law does this problem use?)
2. A sample of helium occupies 535 mL at 988 To
and 25°C. If the sample is transfe
ed to a
1.05 L flask at 25 °C, what will be the gas pressure in the flask?
3. A balloon indoors, where the temperature is 27°C, has a volume of 2.00 L. What will its
volume be outdoors, where the temperature is -23°C? Assume no change in the gas pressure.
(What gas law does this problem use?)
4. A sample of hydrogen gas occupies 692 L at 602 °C. If the pressure is held constant, what
volume will the gas occupy after cooling to 23°C?
5. Calculate the volume occupied by 4.11 kg of methane gas, CH4 (g) at STP. (What gas law
does this problem use?)
6. What is the mass of propane, C3H8, in a 50.0 L container of the gas at STP?
7. What is the pressure exerted by 0.508 mol O2 in a 15.0 L container at 303K?
8. How many moles of nitrogen, N2, are there in a sample that occupies 35.0 L at a pressure of
3.15 atm and a temperature of 852 K?
9. Calculate the molecular weight of a gas, of which a 0.550 g sample occupies 0.200 L at
0.968 atm and 289 K.
10. Calculate the molecular weight of a liquid which, when vaporized at 100°C and 755 To

yields 185 mL of vapor with a mass of 0.523 g.
11. Calculate the density of methane gas, CH4, in grams per liter at 25 °C and 0.978 atm.
12. How many liters of O2(g) are consumed for every 10.0 L of CO2 (g) produced in the
combustion of liquid pentane, C5H12, if each gas is measured at STP?
C5H12 (l XXXXXXXXXXO2 (g) → 5 CO2 (g XXXXXXXXXXH2O (l)
13. A 1.00 L sample of dry air at 25 °C contains XXXXXXXXXXmol N2, XXXXXXXXXXmol O2, XXXXXXXXXXmol
Ar, and XXXXXXXXXXmol CO2. Calculate the partial pressure of N2 in the mixture.
14. What it is the total pressure exerted by a mixture of 4.05 g N2, 3.15 g H2, and 6.05 g He
when confined to a 6.10 L container at 25°C?
15. Calculate the speed of an ozone molecule (O3) in the stratosphere, where the temperature
is 270 K.
16. Calculate the speed of a ca
on monoxide molecule (CO) at 300 K.
Answered 2 days After May 29, 2021

Solution

Jatin answered on May 31 2021
147 Votes
1. Initial conditions:
P1= 748 to
V1= 4.50 L
Final conditions:
P2= 557 to
To find: V2
Applying Boyle’s law:
= 6.04 L
The volume of the balloon will be = 6.04 L
The problem uses Boyle’s law.
2. Initial conditions:
P1= 988 to
V1= 535 mL = 0.535 L
T1= 25ËšC = 298 K
Final conditions:
V2= 1.05 L
T2= 25ËšC = 298 K
To find: P2
Applying the equation:
= 503.41 to
The gas pressure in the flask will be = 503.41 to
.
3. Initial conditions:
V1= 2.0 L
T1= 27ËšC = 300 K
Final conditions:
T2= -23 ËšC = 250 K
To find: V2
Applying the Charles’s law:
= 1.67 L
The gas will occupy a volume of 1.67 L outdoors.
This problem uses Charles’s law.
4. Initial conditions:
V1= 692 L
T1= 602ËšC = 875 K
Final conditions:
T2= 23 ËšC = 300 K
To find: V2
Applying the Charles’s law:
= 237.26 L
After cooling, the gas will occupy a volume of 237.26 L.
5. At STP:
Pressure(P)= 1 atm
Temperature(T)= 273 K
To find: Volume(V) occupied by methane gas
Universal gas constant(R)= 0.08206 L atm K-1 mol-1
Molar mass of methane= 12+4=16 g mol-1
Number of moles(n) of methane gas= 4.11×1000 g /16 g mol-1
= 685 moles
Applying the ideal gas equation and substituting the values:
PV= nRT
= 15345.63 L
Volume(V) occupied by methane gas is = 15345.63 L
This problem uses the Ideal gas law.
6. At STP:
Pressure(P)= 1 atm
Temperature(T)= 273 K
Given: Volume of container= 50.0 L
Universal gas constant(R)= 0.08206 L atm K-1 mol-1
Applying the ideal gas equation and substituting the values:
PV= nRT
= 2.232 mol
Mass of 1 mole of propane= (12×3) + (8×1) = 44 g
Mass of 2.232 moles of propane= 2.232× 44= 98.208 g
7. Volume of the container(V)= 15.0 L
Temperature(T) =...
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