based on the lecture notes and the textbook to finish the homework, write step by...

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based on the lecture notes and the textbook to finish the homework, write step by step!.testbook:http://libgen.io/ads.php?md5=46EAA9C37C0DBCB9E7A1CD7C6625F91A
Problems: (4 points each, unless otherwise noted)
1. Problem 5.76
2. Problem 5.81
3. Problem 3.20
4. Problem 3.24 The required suction pressure is P3 where point 3 is on the wing. Point 2 is a
stagnation point at the leading edge of the wing. The velocity at point 2 (and at any stagnation
point) is zero. The pressure at point 2 is a stagnation pressure P 0 2 .
5. Problem 3.32
6. Problem 3.48 Hint: The lowest pressure in the tube (e.g, the point where the tube will collapse)
is at the top of the U in the tube.
7. Problem 3.54
8. Problem 3.61
9. Problem 3.67

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David · Accepted Answer

Ans. 5.81 
As shown in the above diagrame, there is a pump which is pumping the fluid from the lake to the 
reservoir, so calculate the power of the pump required to reach the water in the reservoir, 
Apply the Bernoulli’s principle at the lake point and the reservoir point, 
So, 
2
1 1 2 2
1 2
1 1 1
2
2 2
0, 0, 0
20
p L
P v P V
Z h h Z
r g r g
where P Z V
Z ft

      
  

 
So put the values in the above equation, 
So, 
2
2p L
P
h h Z
r
    
Calculate the rate of flow of water, and convert the unit, 
3
3
1000 1 1
( ) ( )
10min 7.48 60
0.223 /
gal ft
Q
gal
Q ft s
 
   
 

 
Now, 
2
1
3 550
119
62.4 0.223
2 2 14.7 144
4230
20 87.8
62.4
,
87.8 119 87.8 31.2
p
p
p L L
p
W
h ft
rQ
If P atm
h h h ft
Thus if
h h ft ft

  

   
    
    
 
The given pump will work for P=2atm 
2 2
3 6350 ,
6350
20 122
62.4
p L L
If
lb
P atm then
ft
h h h
 
    
 
Thus, If this pump is to work  
119 122
3
L
L
ft h ft
h ft
 
 
 
Since it is not possible to have 0Lh  Thus pump will not work for 2 3P atm .
Ans 3.61 
  Apply Bernoulli’s principle at both the points, 
2 2
1 1 2 2
1 2
2 1
1
2 2
,
( )
2
P V P V
Z Z
r g r g
So
P P
V g
r
    


 
Here the total height term applies for the equilibrium, 
So, 
1 2
2 1
( )
( )
m
m
P rl r h P r l h
P P r r h
    
  
 
Put the value in the equation (1) 
2
3
2
3
3
( )
2
1.07 9.8 10
2(9.81)( 1)0.02
10.49
3.99 10 1
,

based on the lecture notes and the textbook to finish the homework, write step by step!.testbook:http://libgen.io/ads.php?md5=46EAA9C37C0DBCB9E7A1CD7C6625F91A Problems: (4 points each, unless...

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