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ABC is an equilateral triangle. AD is perpendicular bisector of BC. BX is the angle bisector of angle ABC. Show that triangle BXD is similar to triangle ACD.

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ABC is an equilateral triangle. AD is perpendicular bisector of BC. BX is the angle bisector of angle ABC. Show that triangle BXD is similar to triangle ACD.
Answered Same Day Dec 21, 2021

Solution

Robert answered on Dec 21 2021
118 Votes
As ∆ABC is equilateral, Since, BX is the angle bisector, so In ∆BXD, For ∆BXD and ∆ACD,
XBD = BXD = BDX = So, ∆BXD ~ ∆ACD. Hence, proved.
AC = 2cm...
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