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A set of 50 data values has a mean of 20 and a variance of 36. I. Find the standard score ( z ) for a data value = 18. II. Find the probability of a data value Find the area under the standard normal...

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  1. A set of 50 data values has a mean of 20 and a variance of 36.
    I. Find the standard score (z) for a data value = 18.
    II. Find the probability of a data value
  2. Find the area under the standard normal curve:
    I. to the right of z = -1.36
    II. to the left of z = -1.36
  3. 3. Assume that the population of heights of male college students is approximately normally distributed with mean m of 69 inches and standard deviation s of 4.75 inches. Show all work.
  4. (A) Find the proportion of male college students whose height is greater than 72 inches.
    (B) Find the proportion of male college students whose height is no more than 72 inches.

  5. Find the normal approximation for the binomial probability that x = 4, where n = 14 and p = 0.3. Compare this probability to the value of P(x=4) found in Table 2 of Appendix B in your textbook.
  6. A set of data is normally distributed with a mean of 500 and standard deviation of 100.
  1. · What would be the standard score for a score of 433?
    · What percentage of scores is between 500 and 433?
    · What would be the percentile rank for a score of 433?
    (Points : 6)
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A set of 50 data values has a mean of 20 and a variance of 36. I.  Find the standard score (z) for a data value = 18. II. Find the probability of a data value <>

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Answered Same Day Dec 22, 2021

Solution

David answered on Dec 22 2021
129 Votes
1. A set of 50 data values has a mean of 20 and a variance of 36.
I. Find the standard score (z) for a data value = 18., Z = - 1/3 ( Z-
SCORE)
II. Find the probability of a data value < 18.ASSUMING NORMAL
=0.36944134
2. Find the area under the standard normal curve:
I. to the right of z = -1.36
II. to the left of z = -1.36
1. : 1 - 0.08691496 = 0.913085
2. : 08691496
3. Assume that the population of heights of male college students is
approximately normally distributed with mean  of 69 inches and
standard deviation  of 4.75 inches. Show all work.
It would be a bell-shaped curve symmetric around 69 , which is the population mean , and
have a variance of 22.56 .

4)(A) Find the proportion of male college students whose height is
greater than 72 inches. 1 - 0.73616898 =0.2639
(B) Find the...
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