A lkeV proton is trapped between two magnetic mirrors. The magnetic field strength at the mirrors BM...

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A lkeV proton is trapped between two magnetic mirrors. The magnetic field strength at the mirrors BM = 5B, where B, is the field strength at the midpoint between the mirrors. The mirrors are 108 km apart and each is moving towards the midpoint at Um = 10 km/s. All fields strengths remain constant. Initially the proton has vi = u at the midpoint. (a) To what energy will the proton be accelerated before it escapes? (b) Assuming that B = B, for most of the distance between the mirrors, find approx- imately how long it takes for the proton to reach that energy. [HINT: In each part you can either use an adiabatic invariant, or you can work from first principals]

Dr Shweta · Accepted Answer

A 1 keV proton is trapped between two magnetic mi
ors. The magnetic field strength at the mi
ors BM = 5B0, where B0, is the field strength at the midpoint between the mi
ors. The mi
ors are 108 km apart and each is moving towards the midpoint at Vm = 10 km/s. All fields strengths remain...

A lkeV proton is trapped between two magnetic mirrors. The magnetic field strength at the mirrors BM = 5B, where B, is the field strength at the midpoint between the mirrors. The mirrors are 108 km...

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