1a)What is the magnitude and direction of the electric field a distance
of 5×10-7m
from an...

Question

1a)What is the magnitude and direction of the electric field a distance
of 5×10-7m
from an electron?
b)How much charge would you have to put on a sphere of radius
30mm to get an electric field of 7.5×104NC-1
150mm from the sphere?
2Through
what potential difference must an electron be accelerated for it to acquire a
velocity of 1.5×107ms-1
?

Robert · Accepted Answer

16.1 a) What is the magnitude and direction of the electric field at a distance of 5 × 10-7 m from an 
electron?  
Answer 
Since electron will behave like a point charge, hence 
Electric field due at a distance due to a point charge at  
E = kQ/r2 
Where k = 9 x 109 Nm2/C2  
Q is the amount of charge on an electron = 1.6 x 10-19 C 
And r is the distance at which field is to be calculated = 5 x 10-7 m  
E = 9 x 109 * 1.6 x 10-19 / 5 x 10-7  
E = 2.

1a)What is the magnitude and direction of the electric field a distance of 5×10 -7 m from an electron? b)How much charge would you have to put on a sphere of radius 30mm to get an electric field of...

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