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1. Consider a normal population with µ = 25 and s = 7.0. (A)Calculate the standard score for a value x of 27. (B)Calculate the standard score for a randomly selected sample of 45 -with x= 27. The sign...

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1.Consider a normal population with µ = 25 and s = 7.0.
(A)Calculate the standard score for a value x of 27.
(B)Calculate the standard score for a randomly selected sample of 45 -with
x= 27. The sign is on x please am unable to copy it right .thanks
(C)Explain why the standard scores of 27 are different between A and B above.(Points : 6)
2.Assume that the mean SAT score in Mathematics for 11thgraders across the nation is 500, and that the standard deviation is 100 points. Find the probability that the mean SAT score for a randomly selected group of 150 11thgraders is between 485 and 515.(Points : 3)
3.Assume that a sample is drawn andz(a/2) = 1.65 and s = 30. Answer the following questions:
(A)If the Maximum Error of Estimate is 0.04 for this sample, what would be the sample size?
(B)Given that the sample Size is 400 with this samez(a/2) and s, what would be the Maximum Error of Estimate?
(C)What happens to the Maximum Error of Estimate as the sample size gets larger?
(D)What effect does the answer to C above have to the size of the confidence interval?
(Points : 8)
4.By measuring the amount of time it takes a component of a product to move from one workstation to the next, an engineer has estimated that the standard deviation is 3.22 seconds.
Answer each of the following (show all work):
(A) How many measurements should be made in order to be 98% certain that the maximum error of estimation will not exceed 0.5 seconds?
(B) What sample size is required for a maximum error of 1.5 seconds?
5.A 95% confidence interval estimate for a population mean was computed to be (43.3, XXXXXXXXXXDetermine the mean of the sample, which was used to determine the interval estimate (show all work).
(Points : 4)
6.A study was conducted to estimate the mean amount spent on birthday gifts for a typical family having two children. A sample of 120 was taken, and the mean amount spent was $ XXXXXXXXXXAssuming a standard deviation equal to $37.87, find the 90% confidence interval form, the mean for all such families (show all work).
(Points : 4)
7.A confidence interval estimate for the population mean is given to be (41.16, XXXXXXXXXXIf the standard deviation is XXXXXXXXXXand the sample size is 54, answer each of the following (show all work):
(A) Determine the maximum error of the estimate, E.
(B) Determine the confidence level used for the given confidence interval.
(Points : 4)
8.Write a correct null and alternative hypothesis for testing the claim that the mean life of a battery for a cell phone is at least 80 hours.
(Points : 6
1.Consider a normal population with µ = 25 and s = 7.0.
(A)Calculate the standard score for a value x of 27.
(B)Calculate the standard score for a randomly selected sample of 45 -with
x= 27. The sign is on x please am unable to copy it right .thanks
(C)Explain why the standard scores of 27 are different between A and B above.(Points : 6)
2.Assume that the mean SAT score in Mathematics for 11thgraders across the nation is 500, and that the standard deviation is 100 points. Find the probability that the mean SAT score for a randomly selected group of 150 11thgraders is between 485 and 515.(Points : 3)
3.Assume that a sample is drawn andz(a/2) = 1.65 and s = 30. Answer the following questions:
(A)If the Maximum Error of Estimate is 0.04 for this sample, what would be the sample size?
(B)Given that the sample Size is 400 with this samez(a/2) and s, what would be the Maximum Error of Estimate?
(C)What happens to the Maximum Error of Estimate as the sample size gets larger?
(D)What effect does the answer to C above have to the size of the confidence interval?
(Points : 8)
4.By measuring the amount of time it takes a component of a product to move from one workstation to the next, an engineer has estimated that the standard deviation is 3.22 seconds.
Answer each of the following (show all work):
(A) How many measurements should be made in order to be 98% certain that the maximum error of estimation will not exceed 0.5 seconds?
(B) What sample size is required for a maximum error of 1.5 seconds?
5.A 95% confidence interval estimate for a population mean was computed to be (43.3, XXXXXXXXXXDetermine the mean of the sample, which was used to determine the interval estimate (show all work).
(Points : 4)
6.A study was conducted to estimate the mean amount spent on birthday gifts for a typical family having two children. A sample of 120 was taken, and the mean amount spent was $ XXXXXXXXXXAssuming a standard deviation equal to $37.87, find the 90% confidence interval form, the mean for all such families (show all work).
(Points : 4)
7.A confidence interval estimate for the population mean is given to be (41.16, XXXXXXXXXXIf the standard deviation is XXXXXXXXXXand the sample size is 54, answer each of the following (show all work):
(A) Determine the maximum error of the estimate, E.
(B) Determine the confidence level used for the given confidence interval.
(Points : 4)
8.Write a correct null and alternative hypothesis for testing the claim that the mean life of a battery for a cell phone is at least 80 hours.
(Points : 6
Answered Same Day Dec 22, 2021

Solution

Robert answered on Dec 22 2021
124 Votes
1. Consider a normal population with µ = 25 and σ = 7.0.
(A) Calculate the standard score for a value x of 27.
Answer:
We are given = 25 and = 7
Standard score (Z) = (X- )/ = (27-25)/7 = 0.28571

(B) Calculate the standard score for a randomly selected sample of 45 -
with
x = 27. The sign is on x please am unable to copy it right .thanks
Answer:
n = 45, ̅ = 27, = 7
We want standard score for ̅ = 27, it is given as: Z =
̅


So standard score (Z) [when ̅ = 27] =


= 1.92
(C) Explain why the standard scores of 27 are different between A and B
above. (Points : 6)
Answer:
Standard score in A is for the population whereas standard score in B is for
the sample.
In A, standard score has been calculated for particular population value
whereas in B, it has been calculated for the value of sample mean which has
the different standard deviation.
2. Assume that the mean SAT score in Mathematics for 11th graders across the
nation is 500, and that the standard deviation is 100 points. Find the
probability that the mean SAT score for a randomly selected group of 150
11th graders is between 485 and 515. (Points : 3)
Answer:
Mean SAT score ( = 500

Standard deviation ( ) = 100

n = 150
-
We want P(485< ̅<515) = P[


> ̅

] = P(-1.8371>Z>1.8371), where Z =
̅

So probability that the mean SAT score for a randomly selected group of 150
11th graders is between 485 and 515 = P(-1.8371>Z>1.8371) = 0.9338
3. Assume that a sample is drawn and z( /2) = 1.65 and = 30. Answer the
following questions:

(A)If the Maximum E
or of Estimate is 0.04 for this sample, what would be
the sample size?

Answer:
Sample size (n) =...
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