Great Deal! Get Instant $10 FREE in Account on First Order + 10% Cashback on Every Order Order Now

To complete this Application Assignment, use the dataset anscomb.sav and SPSS to answer the following questions: Problem 9.1: 1.Produce the scatter plot for x3 and y3. Do you think there are any...

1 answer below »

To complete this Application Assignment, use the dataset anscomb.sav and SPSS to answer the following questions:

Problem 9.1:

1.Produce the scatter plot for x3 and y3. Do you think there are any outliers?

2.Calculate the correlation coefficient (r) for all the data points

3.What does the p-value in your SPSS output tell you?

4.What does r tell you about the strength of the association between x3 and y3?

5.Is either variable dependent on the other in this problem? Why or why not?

Problem 9.2:

1.Produce the scatter plot for x1 and y1. Do you think there are any outliers?

2.Fit a linear regression model for y1 against x1. Do you think this is a model with a good fit? Why?

3.Based on the results of 9.2b, is x1 a significant predictor for y1? Why?

Copy and paste (or use the File/Export option in SPSS) any required data charts or summaries into a Word document.

Answered Same Day Dec 29, 2021

Solution

Robert answered on Dec 29 2021
120 Votes
Problem 9.1:
1.Produce the scatter plot for x3 and y3. Do you think there are any outliers?
Ans:
SPSS Step: GraphsChart BuilderScatter Plot
The Obtained Plot is given below.

Here we can see there is almost a linear relation between X3 and Y3 except a point whereY3 is taking pretty high valu
e. From the given observations we can identify that point is co
esponding to the 3
d
observation.
So from the obtained “Scatter-Plot” we can say there exists an outlier co
esponding to the 3
d
observational point.
2.Calculate the co
elation coefficient (r) for all the data points.
Ans:
SPSS Step: AnalyzeCo
elateBivariate Select Pearson’s co
elation coefficient and variables.
Obtained result is,
Co
elations
x3 y3
x3
Pearson Co
elation 1 .816
**

Sig. (2-tailed)

.002
N 11 11
y3
Pearson Co
elation .816
**
1
Sig. (2-tailed) .002

N 11 11
**. Co
elation is significant at the 0.01 level (2-tailed).
Here we can see the co
elation coefficient is 0.816 which is almost near to 1. So from the obtained result it is clear t
hat there is highly positive co
elation between X3 and Y3.
3.What does the p-value in your SPSS output tell you?
Ans:
From the definition of “p-value” is
“In statistical hypothesis testing, the p-value is the probability of obtaining a test statistic at least as extreme as the
one that was actually observed, assuming that the null hypothesis is true.”
So from the observations and the null and alternate hypothesis we can calculate the “p-value” and make the conclusi
on regarding the hypothesis.
If α is the level of significance for a test then we reject the null hypothesis if...
SOLUTION.PDF

Answer To This Question Is Available To Download

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here