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Please see the attached, thank you. Document Preview: Complete the following textbook exercises: 2, 8, and 18 2. A sample of 65 observations is selected from one population with a population standard...

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Complete the following textbook exercises: 2, 8, and 18 2. A sample of 65 observations is selected from one population with a population standard deviation of 0.75. The sample mean is 2.67. A sample of 50 observations is selected from a second population with a population standard deviation of 0.66. The sample mean is 2.59. Conduct the following test of hypothesis using the .08 significance level. H0 : XXXXXXXXXX H1 : 1 - 2 > 0 Is this a one-tailed or two-tailed test? State the decision rule. Compute the value of the test statistic. What is your decision regarding H0? What is the p-value? Interpret the p-value. 8. The null and alternative hypotheses are: H0 : P1 – P2 = 0 H1 : P1 – P2 0 A sample of 200 observations from the first population indicated that X1 is 170. A sample of 150 observations from the second population revealed X2 to be 110. Use the .05 significance level to test the hypothesis. State the decision rule. Compute the pooled proportion. Compute the vale of the test statistic. What is your decision regarding the null hypothesis? Determine and interpret the p-value. 18. The Milton Area Chamber of Commerce wanted to know whether the mean weekly salary of nurses was larger than that of schoolteachers. To investigate, it collected the following information on the amounts earned last week by sample if school teachers and nurses. Teachers ($) 845 826 827 875 784 809 802 820 829 830 842 832 Nurses ($) 841 890 821 771 850 859 825 829 Is it reasonable to conclude that the mean weekly salary of nurses is higher? Use the .01 significance level. What is the p-value? Interpret the p-value.

Answered Same Day Dec 29, 2021

Solution

Robert answered on Dec 29 2021
120 Votes
Complete the following textbook exercises:
2, 8, and 18
2. A sample of 65 observations is selected from one population with a population standard deviation of 0.75. The sample mean is 2.67. A sample of 50 observations is selected from a second population with a population standard deviation of 0.66. The sample mean is 2.59. Conduct the following test of hypothesis using the .08 significance level.
H0 :
 
m
1 - 2
 
£
0
H1 :
 
m
1 -
 
m
2 > 0
a. Is this a one-tailed or two-tailed test?
. State the decision rule.
c. Compute the value of the test statistic.
d. What is your decision regarding H0?
e. What is the p-value? Interpret the p-value.
Answer:
a. It is a one-tailed test.
. Using Z-tables the critical value is
Z (0.08) = 1.405
Decision rule – If Z-statistics > 1.405, null hypothesis is rejected.
c. Test Statistics
Z = (M1 – M2)/√σ1²/n1 + σ2²/n2
= (2.67 – 2.59)/√0.75²/65 + 0.66²/50
= 0.61
d. Since test statistics is less than the critical value, we fail to reject the null hypothesis.
e. Using Z-tables, the probability is
P [Z > 0.61] = 1 – 0.729 = 0.271
As...
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