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Answered Same Day Nov 17, 2021

Solution

Shraddha answered on Nov 19 2021
126 Votes
Assignment 47791
Q 1.
Given the same sample statistics 75% level of confidence is na
ower as for less level of confidence we are more precise for less accuracy so the margin of e
or will becomes less so the resulting confidence interval will also be less.
Q 2.
n = 10
sample mean = 63.4
population standard deviation = 2.4
c : level of confidence = 0.95
Zc : critical value = 1.96
ZC * Population standard deviation 1.96*2.4
E : Margin of e
or = --------------------------------------------------------- = ------------------- = 1.4875
Sqrt(n) sqrt(10)

Lower limit = sample mean – E = 63.4 – 1.4875 = 61.9125
Upper limit = sample mean + E = 63.4 + 1.4875 = 64.8875
So the confidence interval for mean is (61.9, 64.9) so option c is co
ect option.
Q. 3
N : population standard deviation = 800
N : sample size = 40
Sample mean = 130
Sample standard deviation = 10
C : level of confidence = 0.95
Finite population co
ection factor = sqrt ((N-n)/(N-1)) = 0.9753
Degrees of freedom = n – 1 = 39
E : margin of e
or = tc *s/sqrt(n)*finite population co
ection factor
= 2.045 * 10/sqrt(40)*0.9753
= 3.1538
Lower limit = sample mean – E = 130-3.1538 = 126.8
Upper limit = sample mean + E = 130+ 3.1538 = 133.2
So the confidence...
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